y'' -3y + 2y = e^2ix

Will this imaginary constant make some trouble for me?

I have tried this

Y = Ae2ix

and the derivative of that

Y' = 2Ae^2ix

Y''= 4Ae^2ix

I cant figure out how to get the full solution, because I already have the homogenous equation solved. what about this, what will be the constants?