I was having a problem trying to identify the P(x) and q(x) of this question, (X^3)d/dx(y(x))-(4X^2)y(x)=(4x^7) I would be really thankful if someone could help me with this! Thanks!
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Originally Posted by anthony162 (X^3)d/dx(y(x))-(4X^2)y(x)=(4x^7) Dividing $\displaystyle x^3y'-4x^2y=4x^7$ by $\displaystyle x^3$ we get $\displaystyle y'-(4/x)y=4x^4$ . So, $\displaystyle p(x)=-4/x,\;q(x)=4x^4$ .
Thanks alot i've just found out that i had mistaken that the y(x) is part of another equation,thanks for your help!
All right, take into account that $\displaystyle \dfrac{d}{dx}\;(y(x)):=y'(x)$
The equation is also Cauchy-Euler.
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