Let n be the smallest digit in your K-Number that is greater than 1 and?

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March 5th 2011, 03:25 AM
hazeleyes

Let n be the smallest digit in your K-Number that is greater than 1 and?

Let n be the smallest digit in your K-Number that is greater than 1 and consider the ODE

dx/dt = (1/n) cos(t - nx)

Investigate the possibility of straight line solutions and discuss the asymp-
totic behaviour of x(t). (Your investigation and discussion must contain
rigorous mathematics )

please help..(Bow)
March 7th 2011, 01:17 PM
TheEmptySet

Quote:

Originally Posted by hazeleyes

Let n be the smallest digit in your K-Number that is greater than 1 and consider the ODE

dx/dt = (1/n) cos(t - nx)

Investigate the possibility of straight line solutions and discuss the asymp-
totic behaviour of x(t). (Your investigation and discussion must contain
rigorous mathematics )

please help..(Bow)

I am assuming that you k-number is your student id number. I will use 5 in this example.

If we "guess" a linear solution then

$\displaystyle x(t)=mt+b \implies \frac{dx}{dt}=m$

If we put this into the ODE we get

$\displaystyle m=\frac{1}{5}\cos\left(t-5(mt+b) \right)$

First notice that the only way the trig function can be constant is if $\displaystyle m=\frac{1}{5}$ This gives

$\displaystyle \frac{1}{5}=\frac{1}{5}\cos\left(-5b \right)$

This will require

$\displaystyle -5b= \cos^{-1}(1) \iff -5b=2n\pi,n \in \mathbb{Z}$
March 7th 2011, 02:20 PM
hazeleyes

Thank you so much!!! it helps a lot!!!
I'm wondering does it makes different if 'n' is an even number in the process? thanks
March 7th 2011, 05:50 PM
TheEmptySet

Quote:

Originally Posted by hazeleyes

Thank you so much!!! it helps a lot!!!
I'm wondering does it makes different if 'n' is an even number in the process? thanks

n does not really have anything to do with the problem. If you replace 5 with n in my post and follow the same argument you will see that nothing changes!