Hi

You need to plug in -2 for x, 3 for y0(-2) and 1 for y0'(-2)

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- March 3rd 2011, 12:26 PM #1

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## dy/dx=x^2y-y^2+2x

Here's the problem:

the solution to y0 is dy/dx=x^2y-y^2+2x; and y(-2)=3-- now we are also told that y'0(-2)=1 now for the part im having trouble with: find y''0(-2)

now from the problem i was thinking to take the derivative of the equation they gave me... so that would mean implicit differentiation??: 2xy+x^2y'-2yy'+2... but when i plug in -2 for x and 3?? for y i get -5... any help is appreciated ty (Nod)

- March 3rd 2011, 12:32 PM #2

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- March 3rd 2011, 12:52 PM #3

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