Differential Equation y' + y cotx = sinx
Hi guys, this is the differentioan equation I need help to solve
y' + y cotx = sinx
This is the case of using an Integration factor as far as I am concerned.
The form of the equation is
dy/dx (with constant 1) + a(x) * y = b(x)
1. I can see that a(x) is in fact cot x . my integration factor will be e^$cot x dx
as cot x is the same as 1/tanx I put it in the I.F instead
Thus e^$1/tanx * dx -> e^ln tan x = I.F = tanx
2. Then i multiply it
tanx * y' + tanx * y cot x = tanx * sinx
as far as I can see, this is not the product rule?
Can someone help me solve this?