Writing a second order linear DE as...
... it has only one solution for in if in that interval is ...
find an interval centered about x=0 for which the given initial value problem has a unique solution.
(x-2)y'' + 3y = x, y(0) , y'(0)=1
ok so my book is saying that because a2(x)=x-2 and x0 =0 the problem has a unique solution for -infinity<x<2.
im not understanding why this is the answer?