# Thread: Solve y' + y = e^(3x).

1. ## Solve y' + y = e^(3x).

Hi
this is the question:

so i set:

dy/dx + y = e^3x

but im not sure where to go from here.

I could also do

dy + y dx = e^3x dx

Can someone please explain what i should do?
Thanks!

2. Find an integrating factor $\displaystyle I = e^{\int 1 ~dx}$

Do you know why?

What do you get?

3. right right. So i get e^x as the integrating factor. I think i should know what to do now

4. Multiply it through both sides of the equation, what do you get?

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# y' y=e^3x

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