1. ## Integrating factor

I dont see how to make this into an I.F. format:

(3x^2y + 2xy + y^3)dx + (x^2 + y^2)dy = 0

2. Your equation $\displaystyle Pdx+Qdy$ satisfies:

$\displaystyle \dfrac{1}{Q}\left( \dfrac{\partial P}{\partial y}-\dfrac{\partial Q}{\partial x}\right)=3$

This means that the equation has an integrating factor that depends on $\displaystyle x$ .

Fernando Revilla

3. I came up with 3, although I thought that I was looking for an x or some variable as an answer. How does that show that it depends on x. I dont quite understand.

4. Originally Posted by dmbocci
I came up with 3, although I thought that I was looking for an x or some variable as an answer. How does that show that it depends on x. I dont quite understand.

$\displaystyle 3=3+0x$

Fernando Revilla

5. Nope, still dont get it. heh sorry

6. Originally Posted by dmbocci
Nope, still dont get it. heh sorry

$\displaystyle \dfrac{\mu'(x)}{\mu (x)}=3 \Rightarrow\log |\mu(x)|=\int 3\; dx\Rightarrow \ldots$

Fernando Revilla