I dont see how to make this into an I.F. format:

(3x^2y + 2xy + y^3)dx + (x^2 + y^2)dy = 0

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- Feb 21st 2011, 10:11 PMdmbocciIntegrating factor
I dont see how to make this into an I.F. format:

(3x^2y + 2xy + y^3)dx + (x^2 + y^2)dy = 0 - Feb 21st 2011, 10:23 PMFernandoRevilla
Your equation satisfies:

This means that the equation has an integrating factor that depends on .

Fernando Revilla - Feb 21st 2011, 10:28 PMdmbocci
I came up with 3, although I thought that I was looking for an x or some variable as an answer. How does that show that it depends on x. I dont quite understand.

- Feb 21st 2011, 10:36 PMFernandoRevilla
- Feb 21st 2011, 10:37 PMdmbocci
Nope, still dont get it. heh sorry

- Feb 21st 2011, 10:48 PMFernandoRevilla