Hi,

I am struggling to finish this question and would love some guidance please:

Question: Solve for the following differential equation for the original equation:$\displaystyle y' = \frac{-2x-y^2}{2xy-5}$

$\displaystyle y' = \frac{-2x-y^2}{2xy-5}$

$\displaystyle \frac{dy}{dx}= \frac{-2x-y^2}{2xy-5}$

$\displaystyle (2xy-5)dy = (-2x-y^2)dx$

$\displaystyle 2xydy - 5dy = -2xdx -y^2dx$ (assuming that I'm correct so far, what do I do now?)