Solve the equation

$\displaystyle x dy/dx = y^2 - y$

$\displaystyle 1/x dx = 1/(y^2 -y) dy$

$\displaystyle ln x + C = ln (y^2-y)$

$\displaystyle e^l^n^x * e^C = y^2 - y$

$\displaystyle Cx = y^2 - y$

$\displaystyle y^2 - y -Cx = 0$

I'm pretty sure i did something wrong with this one

Solve the equation

$\displaystyle e^xy dy/dx = e^-^y + e^-^2^x^-^y$

No idea where to start on this so any help is greatly appreciated