# Math Help - Separable Equations Application

1. (b-x)/(a-x) = e^(kt(b-a))

How do I isolate the x?

2. Originally Posted by CluelessSenior
(b-x)/(a-x) = e^(kt(b-a))

How do I isolate the x?
$\displaystyle \Rightarrow b - x = a e^{k(b-a)t} - x e^{k(b-a)t}$. Group the terms with x together and take x out as a common factor. Then make x the subject. If you're doing this sort of question, it's assumed you can do the basic algebra ....

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