(b-x)/(a-x) = e^(kt(b-a))

How do I isolate the x?

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- Feb 19th 2011, 03:30 AMCluelessSenior
(b-x)/(a-x) = e^(kt(b-a))

How do I isolate the x? - Feb 19th 2011, 03:35 AMmr fantastic
$\displaystyle \displaystyle \Rightarrow b - x = a e^{k(b-a)t} - x e^{k(b-a)t}$. Group the terms with x together and take x out as a common factor. Then make x the subject. If you're doing this sort of question, it's assumed you can do the basic algebra ....