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Math Help - Seperable and Bernoulli?

  1. #1
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    Seperable and Bernoulli?

    ok here is the other problem...

    dy/dx = (y^2+y)/(x^2+x)

    i see that it is separable, but could it also be Bernoulli because of the y squared?
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  2. #2
    MHF Contributor FernandoRevilla's Avatar
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    Yes, it is also a Bernouilli equation.

    Fernando Revilla
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  3. #3
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    my book says that is only separable..??
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  4. #4
    MHF Contributor FernandoRevilla's Avatar
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    Quote Originally Posted by slapmaxwell1 View Post
    my book says that is only separable..??

    Don't worry, we quickly make another book.

    The equation is equivalent to:

    y'+\left(\dfrac{-1}{x^2+1}\right)y=\left(\dfrac{1}{x^2+1}\right)y^2

    That is, it has the form y'+p(x)y=q(x)y^n (Bernouilli equation).


    Fernando Revilla
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  5. #5
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    Quote Originally Posted by FernandoRevilla View Post
    Don't worry, we quickly make another book.

    The equation is equivalent to:

    y'+\left(\dfrac{-1}{x^2+1}\right)y=\left(\dfrac{1}{x^2+1}\right)y^2

    That is, it has the form y'+p(x)y=q(x)y^n (Bernouilli equation).


    Fernando Revilla
    hahaha if we could get it in print before my next exam that would great
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