ok here is the other problem...

dy/dx = (y^2+y)/(x^2+x)

i see that it is separable, but could it also be Bernoulli because of the y squared?

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- Feb 13th 2011, 03:16 PMslapmaxwell1Seperable and Bernoulli?
ok here is the other problem...

dy/dx = (y^2+y)/(x^2+x)

i see that it is separable, but could it also be Bernoulli because of the y squared? - Feb 13th 2011, 03:37 PMFernandoRevilla
Yes, it is also a Bernouilli equation.

Fernando Revilla - Feb 13th 2011, 03:42 PMslapmaxwell1
my book says that is only separable..??

- Feb 13th 2011, 04:17 PMFernandoRevilla

Don't worry, we quickly make another book. :)

The equation is equivalent to:

$\displaystyle y'+\left(\dfrac{-1}{x^2+1}\right)y=\left(\dfrac{1}{x^2+1}\right)y^2$

That is, it has the form $\displaystyle y'+p(x)y=q(x)y^n$ (Bernouilli equation).

Fernando Revilla - Feb 13th 2011, 05:34 PMslapmaxwell1