i can see that the function is separable, but why not Bernoulli? here is the function dy/dx = (y^2+y)/(x^2+x)
Follow Math Help Forum on Facebook and Google+
Bernoulli's equation has the form $\displaystyle y'+P(x)y=Q(x)y^n,$ if you can't turn your equation into that form, it won't be a Bernoulli one.
View Tag Cloud