.Where u(x,x)=0 . Integrating for u we get Check Determining . Attempt A Now Attempt B . Since u=Ax+Ay Not sure of either of these attempts are correct or how to proceed?
Follow Math Help Forum on Facebook and Google+
Since you added the first two to get why not try substracting the first two and see what that does for you.
Originally Posted by Danny Since you added the first two to get why not try substracting the first two and see what that does for you. Differentiating this wrt x and y and substituting satisfies the original equation, but what about ? Both and must be = constant ie . Using the IC u(x,x)=0 we get I dont understand what this means assuming its correct?
Originally Posted by bugatti79 Differentiating this wrt x and y and substituting satisfies the original equation, but what about ? Both and must be = constant ie . Using the IC u(x,x)=0 we get I dont understand what this means assuming its correct? Correction on above, I forgot the constant of integration Ie in the first line of post 3. IC is u(x,x)=0 implies How would you develop the particular solution based on this?
View Tag Cloud