Solve $\displaystyle (x^{2}+y^{2}-5)dx=(y+xy)dy$

$\displaystyle y(0)=1$

I have tried finding a factor to make this equation exact, and I get $\displaystyle (x+1)^{-3}$. I then integrate by parts with respect to x and get $\displaystyle \,{\frac {-{x}^{2}-{y}^{2}+5}{2 \left( x+1 \right) ^{2}}}+\ln

\left( x+1 \right) + \left( x+1 \right) ^{-1}+\rho \left( y \right) =

{\frac {{x}^{2}+{y}^{2}-5}{ \left( x+1 \right) ^{3}}}

$

I feel like I'm not getting anywhere because nothing cancels like it should. Can someone please help me? Thanks!