Originally Posted by Danny From post #13, when then and so .
Solve for and and sub into and . I work out c=s/2 and d=s/2 therefore and
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Now go after .
Originally Posted by Danny Now go after . I have attached my latest...
Originally Posted by bugatti79 I have attached my latest... continuing on from line 2 on previous post I simplify du/dt to
Integrating with respect to t and imposing the IC's giving the constant of integration =0 I get For clarity I rewrite u, x and y in terms of s and t as
Substituting relevant terms into u i get
You still have an in your answer. Notice that
Now adding and subtracting and gives . Now substitute.
Originally Posted by Danny You still have an in your answer. Notice that
Now adding and subtracting and gives . Now substitute. No wonder I couldnt get the full solution...I had errors in 2nd last line in post 19 which satisfies both IC's and original PDE.
Thanks alot Danny!
This is spin off algebraic query and is wrecking my head.
Given and Adding we get (1)
and subtracting we get (2)
but focusing on (1), I want to find from this...I get ???
They should equal each other! You have two equations for two unknowns. From your last statement gives - there's nothing wrong with this.