Use Charpits Equations to Solve the following given that u=1 on the line x+2y=2.
Is the solution unique?
Initial Condition are
2 solutions p=0, p=1
No solution for p=0, therefore continuing with p=1 at t=0 to find A
Therefore . Now q=2p therefore .
Since 4up=q^2 implies u is
How am I doing so far?