Use Charpits Equations to Solve the following given that u=1 on the line x+2y=2.

Is the solution unique?

Initial Condition are

Therefore

Therefore

2 solutions p=0, p=1

No solution for p=0, therefore continuing with p=1 at t=0 to find A

.

Therefore . Now q=2p therefore .

Since 4up=q^2 implies u is

How am I doing so far?