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Math Help - general solution of the equation

  1. #1
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    general solution of the equation

    Find the general solution of the equation
    u'' + u' + 2u = 0 of the form u(t) = C*(e^a*t)* cos[b*t +Q],1. and verify that it satisfies u(t+2pi/sqrt[7])=-e^(-pi/sqrt[7])*u(t)
    2.Consider a solution satisfying u(0) = 1. Determine u(2pi/sqrt[7])
    For what other values of t can you determine u(t) given u(0)?

    Now r^2+r+2=0=>delta=-1=>
    r1=-1/2+(i*sqrt[7])/2 and r2=-1/2-(i*sqrt[7])/2
    =>C*(e^-1/2*t)* cos[(sqrt[7]/2)*t +Q]=>(e^(-t/2)-(pi/sqrt[7]))*C*cos[(sqrt[7]/2)*t +pi+Q],
    pi+Q=a constant=>-e^(-pi/sqrt[7])*u(t).I hope this is ok.
    And with 2 I have no clue...
    Last edited by AkilMAI; February 6th 2011 at 12:43 PM.
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  2. #2
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    anyone...should i rewrite it again to be more inteligible?
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  3. #3
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    Quote Originally Posted by AkilMAI View Post
    anyone...should i rewrite it again to be more inteligible?
    Re-writing in LaTex would be appreciated.
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  4. #4
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    a program?..ok
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