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Math Help - Differential Equation

  1. #1
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    Differential Equation

    \frac{d^2y}{dx^2}+\frac{dy}{dx}-2y=-3e^x

    given y=2 when x=0, and y=0 when x=2

    I found that y= Ae^x+Be^{-2x}-3xe^x

    then 2=A+B
    and 0=Ae^2+Be^{-4}-6e^2

    is this correct so far?

    my answer is different to the answer given.

    thanks
    Last edited by BabyMilo; February 6th 2011 at 06:06 AM.
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  2. #2
    MHF Contributor FernandoRevilla's Avatar
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    Quote Originally Posted by BabyMilo View Post
    I found that y= Ae^x+Be^{-2x}-3xe^x

    Right.

    then 2=A+B
    and 0=Ae^2+Be^{-4}-6e^2

    Right with those initial conditions but I guess they could be something like this:

    y(0)=2,\quad y'(0)=2


    Check the conditions.


    Fernando Revilla
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