Some help with this problem.Find the solution of the equation v''- 4v'+5v=0,such that v=-1 and v'=1 when x=pi=3.14159 Thank you for your time.
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What ideas have you had so far?
Originally Posted by AkilMAI Some help with this problem.Find the solution of the equation v''- 4v'+5v=0,such that v=-1 and v'=1 when x=pi=3.14159 Thank you for your time. You can treat this as a polynomial. Solve for m
and then when I get m I can use the initial conditions to find the constant c1 and c2(for example) from the general solution form?
Originally Posted by AkilMAI and then when I get m I can use the initial conditions to find the constant c1 and c2(for example) from the general solution form? When you get m, post it. Your solution will be of the form
now I get this system e^[pi+2](A*cos[2x]+B*i*sin[2x])=-1 2e^[pi+2](B*i*cos[2x]-A*sin[2x])=1...how can I solve it?
sorry about that... e^[pi+2](A*cos[2pi]+B*i*sin[2x])=-1=>e^[pi+2]*B*i=-1 2e^[pi+2](B*i*cos[2pi]-A*sin[2x])=1.=>2e^[pi+2]*A=1
Originally Posted by AkilMAI sorry about that... e^[pi+2](A*cos[2pi]+B*i*sin[2x])=-1=>e^[pi+2]*B*i=-1 2e^[pi+2](B*i*cos[2pi]-A*sin[2x])=1.=>2e^[pi+2]*A=1
Last edited by dwsmith; Feb 5th 2011 at 01:12 PM.
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