Some help with this problem.Find the solution of the equation

v''- 4v'+5v=0,such that v=-1 and v'=1 when x=pi=3.14159

Thank you for your time.

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- Feb 1st 2011, 11:41 AMAkilMAI2nd order DE constant coefficients and boundary conditions.
Some help with this problem.Find the solution of the equation

v''- 4v'+5v=0,such that v=-1 and v'=1 when x=pi=3.14159

Thank you for your time. - Feb 1st 2011, 11:42 AMAckbeet
What ideas have you had so far?

- Feb 1st 2011, 11:53 AMdwsmith
- Feb 1st 2011, 12:13 PMAkilMAI
and then when I get m I can use the initial conditions to find the constant c1 and c2(for example) from the general solution form?

- Feb 1st 2011, 12:16 PMdwsmith
- Feb 5th 2011, 05:11 AMAkilMAI
now I get this system

e^[pi+2](A*cos[2x]+B*i*sin[2x])=-1

2e^[pi+2](B*i*cos[2x]-A*sin[2x])=1...how can I solve it? - Feb 5th 2011, 05:19 AMAkilMAI
sorry about that...

e^[pi+2](A*cos[2pi]+B*i*sin[2x])=-1=>e^[pi+2]*B*i=-1

2e^[pi+2](B*i*cos[2pi]-A*sin[2x])=1.=>2e^[pi+2]*A=1 - Feb 5th 2011, 11:26 AMdwsmith