Find the critical value r where the bifurcation occurs. After that rewrite the vector field in the normal form.

x'= r -(x/3)+ 2 ln(x + 4)

I have r = 2/3 - 2(ln6). Is this correct? How do I put this in normal form?

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- Jan 23rd 2011, 09:30 AMveronicak5678Saddle Node Bifurcation
Find the critical value r where the bifurcation occurs. After that rewrite the vector field in the normal form.

x'= r -(x/3)+ 2 ln(x + 4)

I have r = 2/3 - 2(ln6). Is this correct? How do I put this in normal form?