# Thread: Need solution of following eqn.

1. ## Need solution of following eqn.

I need a solution of this eqn.

∇.(ε∇φ)=0

if there is no ε, then φ=x^2-y^2 can easily be taken as solution but I am confused as ε is present. Here ε is electrical conductivity and φ is electrical potential.
Help me please.......

2. Is $\displaystyle \varepsilon$ a constant or a function?

3. Actually I am trying to make simulation of flow induced by plasma actuator using PHOENICS CFD software. Here is the detailed image:

ε is a constant. In the solution domain upper part is air and bottom shaded part is dielectric material. Same equation for both domain except different dielectric constant/electrical conductivity.

for upper domain ε1 is 1 and bottom domain ε2 is 2.7. Possibly the solution should be made considering ε a function. because I have to define upper and bottom domain with 1 and 2.7 respectively.

4. A property of dot products is

$\displaystyle (c_1\mathbf{a}) \cdot (c_2\mathbf{b}) = (c_1c_2)(\mathbf{a}\cdot \mathbf{b})$.

So that means $\displaystyle \nabla \cdot (\varepsilon \nabla \varphi) = \varepsilon (\nabla \cdot \nabla \varphi)$.

5. that means: ε ∇^2φ=0?

6. Originally Posted by bdcrown007
that means: ε ∇^2φ=0?
Yes

7. so, how to proceed for solution?
∇.(ε∇φ)=0
ε ∇^2φ=0
ε(d2φ/dx2+d2φ/dy2)=0

in this case ε=0 ?

>?

8. I think it's pretty clear that $\displaystyle \varepsilon \neq 0$...

How would you solve $\displaystyle \frac{\partial ^2 \varphi}{\partial x^2} + \frac{\partial ^2 \varphi}{\partial y^2} = 0$?

9. If I use then there is no difference between two eqn for two domain (please check image of my 2nd reply).

confused

10. in this case of
the solution becomes: $\varphi=x^2-y^2$

11. but $\varepsilon$ is necessary what should I do?