The coefficients of a certain power series

satisfy

and it is known that . Find .

Is this how it should be approached?

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- January 11th 2011, 02:50 PMdwsmithDE Power Series
The coefficients of a certain power series

satisfy

and it is known that . Find .

Is this how it should be approached? - January 11th 2011, 03:27 PMsnowtea
Try

- January 11th 2011, 03:28 PMdwsmith
- January 11th 2011, 03:30 PMsnowtea
Same as your previous question:

- January 11th 2011, 03:31 PMdwsmith
- January 11th 2011, 03:34 PMsnowtea
Well, it is the correct approach for this problem.

If you do not know the form it is better to take your recurrence:

Multiply every term by , and do the double summation of the entire expression, then simplify.

It becomes the form of the summation you are asking about. - January 11th 2011, 03:36 PMdwsmith
Now, my trouble is how do I use the initial condition?

- January 11th 2011, 03:38 PMsnowtea
You do realize that the summation you wrote gives you the DE:

Solve it like any other DE. - January 11th 2011, 03:38 PMdwsmith
Yes.

- January 11th 2011, 03:40 PMdwsmith
I can just solve that like any other PDE than?

- January 11th 2011, 03:41 PMsnowtea
So do you already have the general form of the solutions for the DE?

If so, just plug-in P(t,t) to solve with initial conditions right? Perhaps I'm missing something? - January 11th 2011, 03:42 PMdwsmith
- January 11th 2011, 07:07 PMdwsmith
I am struggling to obtain the book solution.

I tried B = 0 and D = 1/3; and D = 0 and B = 3 but nothing is happening.

Never mind I forgot to divide out a 2.