Auxiliary condition

How do I solve for the auxiliary equation?

Results 1 to 13 of 13

- January 8th 2011, 08:40 PM #1

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 8th 2011, 09:37 PM #2

- Joined
- Dec 2010
- Posts
- 470

I think you made a typo, should be

but it seems to correct itself later.

You can use the inverse rotation to get your solution in terms of x and y, and then solve using the auxiliary condition.

Or you can transform the auxiliary condition into your new coordinate system.

- January 8th 2011, 09:38 PM #3

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 8th 2011, 09:51 PM #4

- Joined
- Dec 2010
- Posts
- 470

- January 8th 2011, 09:52 PM #5

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 8th 2011, 09:56 PM #6

- Joined
- Dec 2010
- Posts
- 470

- January 8th 2011, 09:58 PM #7

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 8th 2011, 10:05 PM #8

- Joined
- Dec 2010
- Posts
- 470

- January 8th 2011, 10:17 PM #9

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 9th 2011, 09:18 AM #10

- Joined
- Dec 2010
- Posts
- 470

- January 9th 2011, 12:33 PM #11

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 9th 2011, 01:34 PM #12

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 7

- January 9th 2011, 02:58 PM #13

- Joined
- Dec 2010
- Posts
- 470