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Math Help - Strange equation

  1. #1
    MHF Contributor chiph588@'s Avatar
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    Strange equation

    It's easy to solve  f'(x) = xf(x) , but is there a way to solve  f'(x) = xf(x-1)?
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  2. #2
    MHF Contributor chisigma's Avatar
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    Setting \displaystyle f(s)= \mathcal{L} \{y(t)}\} the first order DE equation y^{'}(t)= t\ y(t-1) became the following linear first order DE in the variable s...

     f^{'} (s) = (1 -s\ e^{s})\ f(s) + e^{s}\ y(0) (1)

    ... that can be solved with a 'standard' approach...

    Kind regards

    \chi \sigma
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  3. #3
    Super Member Random Variable's Avatar
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    Can it be treated as the product of the Heaviside function with another function?

    EDIT: Nevermind. That doesn't make any sense.
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