The answer is this
Lambda is any constant.
I am not sure how this is the solution.
Using exponential substitution:
-\infty,0]\cup [1,\infty)" alt=" \ \ s-\infty,0]\cup [1,\infty)" />
Can this be simplified more or is there a more tactful way to represent this?
I have taken so that, I get required value for s;
If I didnt know the answer I would not present it as I had done in post #3. I would have given the answer as,
But since you had given thes answers in the book and told that you are not sure how they have been obtained I had shown that both anwers are equivelent. Does this clarify your doubts?
Now I am solving the same equation using separation of variables. However, I have hit a snag.
The first equation is suppose to yield , and the second equation needs to be of the form in order to obtain the same solutions from the exponential method.
I haven't come across this in the book but can I just set both equations equal to
Yes you can. What is the reasoning behind setting ?? It is that the two parts are independent of y and x respectively. So that if they are equal to each other there must be a common constant to which both are equal. In this case you had taken it to be . But you can take the constant as you like it to be. For example instead of you can take if you dont like taking a the negative sign. Then there exists such that . Substitute for and you will get the same answer.
Hope you got the idea. I am a non native speaker of english. So if you find anything that confuses you please do not hesitate to ask me.