Hello - i need little help with this:
Find the particular solution:
blue - the problem
black - part of the solution
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Have you taken the derivative of y?
You need to set y(0) = 2 and y'(0) = -2
Use the conditions y(0) = 2, and y'(0) = -2
y(0) = (c1) + (c2) = 2
y'(0) = -3(c1) + (c2)/3 = -2
Solve for c1 and c2
And you have the particular solution for y
This is a homogeneous DE, you don't need to find a particular solution.
Just substitute your boundary conditions, noting that , to evaluate and .
So what's the problem? You've already done the hard part. Insert the conditions and into your solution (and the derivative of it) and you'll end up with a system of linear equations that is easy to solve.
OK thanks i just wanted to be sure.. Thanks for the help
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