1. Find the general solution of the following differential equations:

(a) dy/dx = y(1-y)

(b) dy/dx = 3 -2y

what i tried to do was move them to LHS....

[$\displaystyle \frac{1}{y(1-y)}$]($\displaystyle \frac{dy}{dx}$)=1

Integrate wrt x,

$\displaystyle \int$$\displaystyle \frac{1}{y(1-y)}$ dy=$\displaystyle \int$1 dx

then...i'm stuck...

as for (b)

2y + dy/dx =3

....I couldn't figure it out how to express y in terms of x eventually.

any help is much appreciated.