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Math Help - seperable equation

  1. #1
    Junior Member
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    seperable equation

    I reviewing for my final and stuck on this question.

    dy/dx=y^2/x^2

    here is my work

    dy/y^2=dx/x^2, integrading both sides i get

    -1/y=-1/x+c, i then multiple each side by negative -1 to get
    1/y=1/x-c, then multiplying by y i get
    1=(1/x-c)y, dividing by 1/x-c i get
    1/(1/x-c)=y, but this is not one of the options for my solution, what am i doing wrong?
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  2. #2
    MHF Contributor
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    \displaystyle \frac{dy}{dx}=\frac{y^2}{x^2}\Rightarrow \int\frac{dy}{y^2}=\int\frac{dx}{x^2}\Rightarrow \frac{-1}{y}=\frac{-1}{x}+C\Rightarrow

    \displaystyle \frac{-1}{\frac{-1}{y}}=\frac{-1}{\frac{-1+xC}{x}}\Rightarrow y=\frac{-x}{xC-1}
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