Results 1 to 2 of 2

Thread: first order differential equation

  1. December 7th 2010, 02:58 PM #1
    absvalue
    absvalue is offline
    Junior Member
    Joined
    May 2009
    Posts
    66

    first order differential equation

    y' = \frac{1}{y}

    Any ideas on how to solve this? I tried to get it in the form:

    y' + p(t)y = g(t)

    Once it's in that form I know how to solve it. But, I don't think it's possible to get it in that form.

    Could someone point me in the right direction?

    Thanks!
    Follow Math Help Forum on Facebook and Google+
  2. December 7th 2010, 03:08 PM #2
    FernandoRevilla
    FernandoRevilla is offline
    MHF Contributor FernandoRevilla's Avatar
    Joined
    Nov 2010
    From
    Madrid, Spain
    Posts
    2,154
    Thanks
    38
    Quote Originally Posted by absvalue View Post
    y' = \frac{1}{y}
    y' = \dfrac{1}{y}\Leftrightarrow dx-ydy=0

    (separated variables).

    Regards.

    Fernando Revilla
    Follow Math Help Forum on Facebook and Google+
« Kinematics, find x given v. | z=y' solution »

Similar Math Help Forum Discussions

  1. Simplifying an equation containing both a first order and second order differential
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: September 21st 2011, 03:37 PM
  2. First Order Differential Equation
    Posted in the Differential Equations Forum
    Replies: 5
    Last Post: December 29th 2010, 10:39 PM
  3. second order differential equation
    Posted in the Differential Equations Forum
    Replies: 1
    Last Post: April 26th 2010, 07:21 AM
  4. Formulating a second-order ordinary differential equation as a first-order system?
    Posted in the Differential Equations Forum
    Replies: 2
    Last Post: November 25th 2008, 09:29 PM
  5. Second Order Differential Equation
    Posted in the Differential Equations Forum
    Replies: 8
    Last Post: November 18th 2008, 04:23 AM

Search Tags


/mathhelpforum @mathhelpforum