1. first order differential equation

$\displaystyle y' = \frac{1}{y}$

Any ideas on how to solve this? I tried to get it in the form:

$\displaystyle y' + p(t)y = g(t)$

Once it's in that form I know how to solve it. But, I don't think it's possible to get it in that form.

Could someone point me in the right direction?

Thanks!

2. Originally Posted by absvalue
$\displaystyle y' = \frac{1}{y}$
$\displaystyle y' = \dfrac{1}{y}\Leftrightarrow dx-ydy=0$

(separated variables).

Regards.

Fernando Revilla