first order differential equation

• Dec 7th 2010, 03:58 PM
absvalue
first order differential equation
$y' = \frac{1}{y}$

Any ideas on how to solve this? I tried to get it in the form:

$y' + p(t)y = g(t)$

Once it's in that form I know how to solve it. But, I don't think it's possible to get it in that form.

Could someone point me in the right direction?

Thanks!
• Dec 7th 2010, 04:08 PM
FernandoRevilla
Quote:

Originally Posted by absvalue
$y' = \frac{1}{y}$

$y' = \dfrac{1}{y}\Leftrightarrow dx-ydy=0$

(separated variables).

Regards.

Fernando Revilla