# Thread: function of y second order equation

1. ## function of y second order equation1

$y''y=(y')^{2}$
$y(0)=1 y'(0)=2$
$y'=z$
$z'y=z^{2}$
$\frac{{dz}}{dx}=\frac{dz}{dy}\frac{dy}{dx}$
$zz'=dz/dx$
i know i need to do x'(y)

but i dont know how to put it there
how i solve it?

2. Or you could try this:

$\dfrac{y''}{y'}=\dfrac{y'}{y},$ and integrate.