Given at point (x,y)

and the curve goes through (2, -1/3)

Prove the equation of the curve,

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- November 17th 2010, 08:31 AMBabyMiloDifferential Equation
Given at point (x,y)

and the curve goes through (2, -1/3)

Prove the equation of the curve,

- November 17th 2010, 08:34 AMUnknown008
Separate the variables and integrate...

Then, use the values of (2, -1/3) to find the value of the constant of integration.

Or, you can find directly:

EDIT: You should know by now that you should post what you have tried. - November 17th 2010, 08:36 AMHallsofIvy
Have you

**tried**anything your self? To show that a given function satisifies a differential equation is typically much simpler than actually solving the equation- just differentiate the given y and show that it satisfies the equation.

However, in this case the equation "separates" as and those are easy to integrate. - November 17th 2010, 08:40 AMBabyMilo
i have

- November 17th 2010, 08:46 AMUnknown008
EDIT: Hm... I'm not getting this. Either I made a mistake or you made one.

Make y the subject now, then expand the square that you have. - November 17th 2010, 08:54 AMBabyMilo
Got it. Ha you guys didnt really help.

It was just the rearrange i got a bit confused with tbh.

but thank you as always.