Hi again,

$\displaystyle \displaystyle y(2)=2$

$\displaystyle \displaystyle y'+\frac{1}{x}y=0$

$\displaystyle \displaystyle P(x)=\frac{1}{x},Q(x)=0,U(x)=e^{\int\frac{1}{x}dx}$

$\displaystyle \displaystyle y=\frac{1}{U(x)}\int Q(x)U(x)dx$

$\displaystyle \displaystyle y=\frac{1}{x}\int 0 x dx$

$\displaystyle \displaystyle y=\frac{1}{x}\int dx$

Is this the way to go about the problem?

I think this is the set up by first-order linear differential equation. Im having problems with finding the solution.