there is an equation when p(x) and q(x) are deferentiable

on I.

y1 and y2 are two independant solutions of a given equation.

show that u(x) makes a first order differential equation

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- Nov 13th 2010, 06:43 AMtransgalacticindependant solution questionthere is an equation when p(x) and q(x) are deferentiable

on I.

y1 and y2 are two independant solutions of a given equation.

show that u(x) makes a first order differential equation - Nov 13th 2010, 06:55 AMKrizalid
you were given the substitution, where are you stuck?

- Nov 13th 2010, 07:01 AMtransgalactic

i put the solutions i got these two equations

what now? - Nov 13th 2010, 10:35 AMAckbeet
Looks good so far. Why not expand out the derivative in the second equation?