Equation:

$\displaystyle I \theta '' + c \theta ' = Tm$

I = 0.9

c = 0.15

Tm = 0.3

My solution:

Reduced Equation 1° order:

$\displaystyle y_2' = \frac{T_m}{I} - \frac{Cy_2}{I}$

I used three steps to RK2 and found:

$\displaystyle y_1 = 0.01665$

$\displaystyle y_2 = 0.03306$

$\displaystyle y_3 = 0.04249$

Is that correct?

How do I find the analytical solution?