A) B) how to solve these
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Originally Posted by transgalactic B) Does this separate? It does! what next?
what is the integral of 1/(cos2y+1) ? regarding A) i put v=cosy
Last edited by transgalactic; Nov 13th 2010 at 05:57 AM.
how to solve A
For (A), the substitution renders the equation linear.
from this substitution i got by rearanging i got u'/u +2u=(sin x)^2 what to do now?
You did the substitution incorrectly. u = sin(y). sin(x) remains as is.
i got u'+2ucosx=-(sin x)^2 i dont know how to solve the right side integral
Last edited by transgalactic; Nov 17th 2010 at 07:13 AM.
Original DE: Substitution: Then Plugging into the DE yields I think you forgot to distribute the cosine everywhere. So, propagate these changes: what do you get?
on the left side i get cos x (sin x)^2 e^{2sinx} i dont know how to solve this integral
Substitute v = sin(x). Then you'll need by parts twice.
Originally Posted by transgalactic what is the integral of 1/(cos2y+1)? which is the derivative of .
thanks
So, did you finish?
yes i solved just like you said it went perfect
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