A)

B)

how to solve these

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- November 11th 2010, 01:09 PMtransgalactictrigonometric equation
A)

B)

how to solve these - November 11th 2010, 01:20 PMpickslides
- November 13th 2010, 05:28 AMtransgalactic
what is the integral of 1/(cos2y+1)

?

regarding A)

i put v=cosy

- November 17th 2010, 01:01 AMtransgalactic
how to solve A

- November 17th 2010, 02:43 AMAckbeet
For (A), the substitution renders the equation linear.

- November 17th 2010, 03:02 AMtransgalactic
from this substitution i got

by rearanging i got

u'/u +2u=(sin x)^2

what to do now? - November 17th 2010, 04:48 AMAckbeet
You did the substitution incorrectly. u = sin(y). sin(x) remains as is.

- November 17th 2010, 06:44 AMtransgalactic
i got

u'+2ucosx=-(sin x)^2

i dont know how to solve the right side integral - November 17th 2010, 07:21 AMAckbeet
Original DE:

Substitution: Then

Plugging into the DE yields

I think you forgot to distribute the cosine everywhere. So, propagate these changes: what do you get? - November 18th 2010, 10:57 AMtransgalactic
on the left side i get cos x (sin x)^2 e^{2sinx}

i dont know how to solve this integral - November 18th 2010, 11:01 AMAckbeet
Substitute v = sin(x). Then you'll need by parts twice.

- November 18th 2010, 11:41 AMTheCoffeeMachine
- November 18th 2010, 11:42 AMtransgalactic
thanks :)

- November 18th 2010, 12:18 PMAckbeet
So, did you finish?

- November 18th 2010, 12:25 PMtransgalactic
yes

:)

i solved just like you said it went perfect