when solving a second order homogeneous equation and if the queficients are complex numbers I know that the general solution has the form: e^ht*(C1cos(ut)+C2sen(ut)) my question is: Does it include the imaginary part of the solution or its just the real part of the solution? I ask this because when getting the two solutions e^((h+iu)t) and e^((h-iu)t) I cant get to the general solution formula by means of linear combinations and eulers formula can someone help me?