(d^2/dx^2)y + 1/x dy/dx = (12logx)/(x^2) Thank you....
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So you're solving $\displaystyle y''+y'/x=\dfrac{12\ln(x)}{x^{2}}.$ First step: reduce order by setting $\displaystyle u=y'.$ Then what do you suppose you can do?
Notice that $\displaystyle x y'' + y' = \dfrac{d}{dx}\left( x y'\right)$.
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