Can someone tell me the region where h(3 - 2t) is equal to 1? I know how to do it if the number in front of the t is 1 and if it was t - a constant but not sure what happens here

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- Nov 4th 2010, 05:18 PMCookieCStep function
Can someone tell me the region where h(3 - 2t) is equal to 1? I know how to do it if the number in front of the t is 1 and if it was t - a constant but not sure what happens here

- Nov 4th 2010, 05:28 PMAckbeet
Assuming you mean the Heaviside step function there, it's 1 when the argument is non-negative. That is, when $\displaystyle 3-2t\ge 0.$ Can you finish from here?

- Nov 4th 2010, 05:30 PMCookieC
Yeah I mean Heaviside step function:

so 3 - 2t >= 0

-2t >= -3

t <= 3/2 ? - Nov 4th 2010, 05:31 PMAckbeet
Correct.