solve (y^2 + 2xy ) dx + ( 2 x^2 + 3xy ) dy = 0

(y^2 + 2xy ) dx + ( 2 x^2 + 3xy ) dy = 0
Thank you

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Originally Posted by rafi98

(y^2 + 2xy ) dx + ( 2 x^2 + 3xy ) dy = 0
Thank you

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Divide through by x^2 and it's obvious that the DE is homogenous. Substitute y = xv etc. (see class notes or textbook).