http://i52.tinypic.com/2hn2m8m.jpg
Last edited by mr fantastic; Oct 21st 2010 at 05:49 AM. Reason: Re-titled.
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It's Bernoulli, with standard form
ok
how does from we get z' and y' we only have dz and dy here??? in order to get y' we need to have dy/dx we dont have it here. then after solving by parts i get what to do now?
Last edited by transgalactic; Oct 21st 2010 at 12:28 AM.
First off, if you let then .
ok i missed that -4 in the defferentiation what about my questions
Well, you need to transform the DE which is in terms of into a DE in terms of . You have . By the chain rule, . So and thus . Substituting everything into the DE . This is now first order linear, which you can solve using an integrating factor.
i got a similiar lenear differential equation and i solved it by multiplying in exponet etc and it doesnt come out ??
Your integrating factor is . So multiplying through by the integrating factor gives .
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