hi guys,

haven't done diff eqn stuff in a long time. i am not sure how to do this:

find a particular solution to this differential equation by using the method of variation of parameters:

y'' - 4y = sinh(2x)

i know the answer is y_p(x) = (1/16)(4*x*cosh(2x) - sinh(2x)) but can someone show me how to reach this solution??!!

thanks a lot!