1)
solve
dy/dx + (y logy)/x = y(logy)^2/(x^2)
2)
SOLVE
(x*y^2)dx - e^(1/(x^3))dx - (x^2)*y dy = 0
Thank you
For the first one, make the substitution $\displaystyle u=\dfrac{\log y}{x}$ (assume you're letting $\displaystyle \log y$ mean natural log [base e]). It will then become a simple separable equation.
For the second one, rewrite it as $\displaystyle \dfrac{dy}{dx}-\dfrac{1}{x}y=-\dfrac{1}{x^2}e^{-1/x^3}y^{-1}$; this is a Bernoulli equation.
Can you take it from here?