Thread: IVP

Hello,
I was given the problem and to solve the initial value problem

5x4y3dx+3x5y2dy=0y(1)=1

I was told to find the answer in terms of F(x,y)=1 and F(x,y) does not have a constant.

I got to the part where i've integrated both sides and got

5ln(x) + 3ln(y)

I'm just confused on what to do next, i tried solving for the constant which is 0

but have no clue what the question means when its asking for it in terms of F(x,y)=1

both answers i tried were wrong: 1- 5ln(x) + 3ln(y) & 2- 5ln(x) + 3ln(y) + 1

thankss

Originally Posted by washerman

Hello,
I was given the problem and to solve the initial value problem

5x4y3dx+3x5y2dy=0y(1)=1

I was told to find the answer in terms of F(x,y)=1 and F(x,y) does not have a constant.

I got to the part where i've integrated both sides and got

5ln(x) + 3ln(y)

I'm just confused on what to do next, i tried solving for the constant which is 0

but have no clue what the question means when its asking for it in terms of F(x,y)=1

both answers i tried were wrong: 1- 5ln(x) + 3ln(y) & 2- 5ln(x) + 3ln(y) + 1

thankss

The ODE is first order linear and separable


Integrating both sides gives



Using the initial condition gives A=1



To put the solution into implicit form we have